Question

please answer fast
well explained answer is needed

Answer 1

Howdy !!!

your answer is --

given, l = 100cm and ∆l = 1mm = 0.1cm

and time period is 2s
so, 2s = 1oscillation
therefore ,100 oscillation = 200s and
∆t = 0.1 s

now , T = 2π√l/√g
squaring both side

T^2 = 4πl/g => g = 4πl/T^2

4π is constant

now , percentage error of g is--

∆g/g × 100 = ( ∆l/l + 2× ∆T/T ) ×100

= ( 0.1/100 + 2× 0.1/200) ×100
= 0.2 + 0.2 /200 × 100
= 0.4 /2
= 0.2 %

so , % error in g is 0.2%

therefore , option (c) is right

hope it help you
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