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Step-by-step explanation:
formulas
d(log x)/dx = 1/x
d(tan x) = sec² x
d(a+b)/dx = d(a)/dx + d(b)/dx
let y = log x + tan x
then
dy/dx = d(log x + tan x)/dx
= d(log x)/dx + d(tan x)/dx
= 1/x + sec²x
so, the answer is 1/x + sec² x
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