Question

please answer fast with proper steps ​

Answer 1

TanA
$\sqrt{sec {}^{2} - 1}$
$\sqrt{25 \div 16 - 1}$
Tan A = 3/4
CosA = 4/5
3/4 + 5/4 =2

Answer 2

Listen,

Sec A = 1/Cos A =5/4

So Tan A +5/4=2

Tan A=2-5/4=3/4

So 3/4 +5/4 =8/4 =2 =RHS