please answer fast with step by step explanation
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Question :-
(3/7)^4 x (3/7)^5 = (3/7)^2m + 1
(3/7)^(4+5) = (3/7)^2m + 1
Here the bases , which are 3/7 are in multiply so because the bases are same their power/exponent got added
(3/7)^9 = (3/7)^2m + 1
Here , the bases of LHS and RHS are same , hence We can evaluate power/exponent , that is
we have :-
9 = 2m + 1
9 - 1 = 2m
8 = 2m
8/2 = m
m = 4
So , m = 4
Hope it helped you...
Aishwarya20644:
thanks
Answered by
0
Answer: n =4
Step-by-step explanation:
When the co efffecient are equal there power is added .
Therefore,(3/7)^4 * (3/7)^5 = (3/7)^2n+1
(3/7)^4+5 =(3/7)^2n+1
(3/7)^9 = (3/7)^2n+1
Powers=> 9=2n+1
9-1=2n
8=2n
n= 4 ans.
Hope this helps
:)
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