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Initial velocity of body =20m/s
angle with horizontal =60°
velocity vector along horizontal direction =20cos60 i=20*1/2=10i
velocity vector along vertical direction =
20sin60 j=20*√3/2 =10√3j
so velocity vector is 10i + 10√3j
angle with horizontal =60°
velocity vector along horizontal direction =20cos60 i=20*1/2=10i
velocity vector along vertical direction =
20sin60 j=20*√3/2 =10√3j
so velocity vector is 10i + 10√3j
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