Math, asked by dharanidr12, 3 months ago

please answer fastly friends I will mark as brainliest​

Attachments:

Answers

Answered by dheshna458
2

Answer:

Other two factors are (x-2)(x+3)

Step-by-step explanation:

Let p(x) = 3x³+x²-20x+12

Given (3x-2) is a factor of p(x) .

3x-2)3x³+x²-20x+12(x²+x-6

3x³-2x²

3x²-20x

 3x²-2x

 -18x+12

-18x+12

Remainder (0)

Now ,

p(x) = (3x-2)(x²+x-6)

= (3x-2)(x²+3x-2x-6)

= (3x-2)[x(x+3)-2(x+3)]

= (3x-2)(x+3)(x-2)

Therefore,

Other two factors are (x-2)(x+3)

Answered by yashu3648001
0

Step-by-step explanation:

I have solved it ,, if you get any doubt ask again . Ok!?

Attachments:
Similar questions