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Answer:
Other two factors are (x-2)(x+3)
Step-by-step explanation:
Let p(x) = 3x³+x²-20x+12
Given (3x-2) is a factor of p(x) .
3x-2)3x³+x²-20x+12(x²+x-6
3x³-2x²
3x²-20x
3x²-2x
-18x+12
-18x+12
Remainder (0)
Now ,
p(x) = (3x-2)(x²+x-6)
= (3x-2)(x²+3x-2x-6)
= (3x-2)[x(x+3)-2(x+3)]
= (3x-2)(x+3)(x-2)
Therefore,
Other two factors are (x-2)(x+3)
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