Physics, asked by royniraj17, 7 months ago

please answer fastly with correct answer i will make him brainlist​

Attachments:

royniraj17: mandeepsingh can you tell me what is the process
mandeepsingh131980: yes in (a) part we used the formula v^2-u^2=2as
mandeepsingh131980: and in part (b) we use the formula v=u+at
mandeepsingh131980: i don't know the answer of (c) part. sorry for that

Answers

Answered by mandeepsingh131980
1

Answer:

(a) velocity = 30m/s

(b) time= 3s

Answered by krishanu2002
1

Answer:

a) 2gh= v^2 - u^2

    2 * -10 * 45 = 0 - u^2

     -900 = - u^2

     u = 30 m/s

b) v= u+ gt

   0 = 30 + (-10)t

   t= 3s <-- it will not be -3s as time cannot be negative

c) since, time of ascent=time of descent = 3s

    so, total time in air = time of ascent + time of descent  

                                   = 3+3=6s

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