Question

please answer fastpls​

Answer 1

Solution :-

$\sf \dfrac{x + 1}{10} - \dfrac{3(x - 1)}{5} = 2$

$\sf\rightarrow \dfrac{x + 1}{10} - \dfrac{3x - 3}{5} = 2$

$\sf\rightarrow \dfrac{(x + 1) - 2(3x - 3)}{10} = 2$

$\sf\rightarrow \dfrac{x + 1 - (6x - 6)}{10} = 2$

$\sf\rightarrow \dfrac{x + 1 - 6x + 6}{10} = 2$

$\sf\rightarrow \dfrac{ - 5x + 7}{10} = 2$

$\sf\rightarrow - 5x + 7 = 20$

$\sf\rightarrow - 5x = 20 - 7$

$\sf\rightarrow - 5x = 13$

$\sf\therefore x = - \dfrac{13}{5}$

Hence, the value of x will be -13/5 respectively.

Some algebraic identities :-

• (a + b)² = a² + b² + 2ab
• (a - b)² = a² + b² - 2ab
• a² - b² = (a + b)(a - b)
• a² + b² = (a + b)² - 2ab

Answer 2

Answer:

d one :-):-):-):-):-):-):-):-):-):-):-)