please answer fastpls
Answers
A's present age = 19 years
B's present age = 15 years
Solution
Let the present age of A be x years and the present age of B be y years .
Then , three years ago ;
A's age = (x-3) years
B's age = (y-3) years
Also, three years hence ;
A's age = (x+3) years
B's age = (y+3) years
According to the question;
Three years ago, the ratio of the ages of A and B was 4:3.
Thus;
=> (x-3):(y-3) = 4:3
=> (x-3)/(y-3) = 4/3
=> 3•(x-3) = 4•(y-3)
=> 3x - 9 = 4y - 12
=> 3x - 4y = 9 - 12
=> 3x - 4y = - 3 --------(1)
Also;
Three years hence, the ratio of ages of A and B will be 11:9.
Thus;
=> (x+3):(y+3) = 11:9
=> 9•(x+3) = 11•(y+3)
=> 9x + 27 = 11y + 33
=> 9x - 11y = 33 - 27
=> 9x - 11y = 6 ---------(2)
Now,
Multiplying both sides of eq-(1) , we get;
=> 3•(3x - 4y) = 3•(- 3)
=> 9x - 12y = - 9 ---------(3)
Now,
Subtracting eq-(3) from eq-(2) , we get;
=> (9x - 11y) - (9x - 12y) = 6 - (- 9)
=> 9x - 11y - 9x + 12y = 6 + 9
=> y = 15
Now,
Putting y = 15 in eq-(1) , we get;
=> 3x - 4y = - 3
=> 3x = 4y - 3
=> 3x = 4•15 - 3
=> 3x = 60 - 3
=> 3x = 57
=> x = 57/3
=> x = 19
Hence,
A's present age = x years = 19 years
B's present age = y years = 15 years
Hope this helps you ;)
Question:
Three years ago, the ratio of the ages of A and B was 4:3. Three years hence, the ratio of their ages will be 11:9. Find the present ages of A and B.
Answer:
A's present age = 19 years
B's present age = 15 years
Solution:
Let the present age of A be x years and the present age of B be y years .
Then , three years ago ;
A's age = (x-3) years
B's age = (y-3) years
Also, three years hence ;
A's age = (x+3) years
B's age = (y+3) years
According to the question;
Three years ago, the ratio of the ages of A and B was 4:3.
Thus;
=> (x-3):(y-3) = 4:3
=> (x-3)/(y-3) = 4/3
=> 3•(x-3) = 4•(y-3)
=> 3x - 9 = 4y - 12
=> 3x - 4y = 9 - 12
=> 3x - 4y = - 3 --------(1)
Also;
Three years hence, the ratio of ages of A and B will be 11:9.
Thus;
=> (x+3):(y+3) = 11:9
=> 9•(x+3) = 11•(y+3)
=> 9x + 27 = 11y + 33
=> 9x - 11y = 33 - 27
=> 9x - 11y = 6 ---------(2)
Now,
Multiplying both sides of eq-(1) , we get;
=> 3•(3x - 4y) = 3•(- 3)
=> 9x - 12y = - 9 ---------(3)
Now,
Subtracting eq-(3) from eq-(2) , we get;
=> (9x - 11y) - (9x - 12y) = 6 - (- 9)
=> 9x - 11y - 9x + 12y = 6 + 9
=> y = 15
Now,
Putting y = 15 in eq-(1) , we get;
=> 3x - 4y = - 3
=> 3x = 4y - 3
=> 3x = 4•15 - 3
=> 3x = 60 - 3
=> 3x = 57
=> x = 57/3
=> x = 19
Hence,