please answer fastttt........
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Angle mlq=180 degree -110 degree
=70 degree (angles lying on same line)
angle qml=92 (corresponding angle with the angle which is supplementary to 88 degree)
angle x+70 degree+92degree=180degree (sum of all angles of triangle is 180 degree)
x=180-(70+92)degree
x=18degree
Hope it helps:))
=70 degree (angles lying on same line)
angle qml=92 (corresponding angle with the angle which is supplementary to 88 degree)
angle x+70 degree+92degree=180degree (sum of all angles of triangle is 180 degree)
x=180-(70+92)degree
x=18degree
Hope it helps:))
shreeja3:
sorry but x=18° is the anawer
Answered by
1
here angle PML equals to 88 degree
and angle LMQ equals to 92 degree
if angle Q L C is equal to 110 therefore angle qlm equals to 70 degree by angle sum property in triangle QML 92 + 70 + x equal 180
now
180 - 162 = x
now X equal to 18 degree
and angle LMQ equals to 92 degree
if angle Q L C is equal to 110 therefore angle qlm equals to 70 degree by angle sum property in triangle QML 92 + 70 + x equal 180
now
180 - 162 = x
now X equal to 18 degree
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