PLEASE ANSWER.....
Find dy/dx if
x² + y²+3xy=7
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Step-by-step explanation:
2x+2y dy/DX +3[X dy/DX +y]=0
2x+2y dy/dx +3x dy/DX+3y=0
Dy/DX(2y+3x)=-(2x+3y)
Dy/DX=-(2x+3y)/(2y+3x)
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