Math, asked by parshu7666, 5 months ago

please answer.... find missing angles... A and B​

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Answered by Anonymous
8

Answer:

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Step-by-step explanation:

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Answered by Anonymous
1

TO FIND:

  • Angle A and B

SOLUTION:

In triangle SQR by applying angle sum property

  \tt\angle QSR +  105 \degree + 28 \degree = 180 \degree

 \tt \angle QSR = 180 \degree - 105 \degree - 28 \degree

 \tt \angle QSR = 47 \degree

 \tt \angle QSR =  \angle B = 47 \degree

  \sf(\because vertically \: opposite \: angle)

 \tt \angle SQR+ \angle TQP=180°

   \sf(\because linear \: pair)

 \tt 105°+ \angle TQP=180°

 \tt \angle TQP=180 \degree  - 105 \degree

 \tt \angle TQP = 75 \degree

In triangle TPQ by applying angle sum property

 \tt \angle \: TPQ+ \angle TQP+ \angle PTQ=180°

A+75°+82°=180°

A=23°

So answers are:-

  • A=23°
  • B=47°

Property used:

  • Angle sum property of triangle.
  • Vertically opposite angle.
  • Linear pair.

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