please answer ... find x,y and z
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Heya!
In triangle ABD,
By angle sum property,
angle ABD + angle ADB + angle BAD = 180
=) 30 + angle ADB + 10 = 180
=) angle ADB = 180 - 40
=) angle ADB = 140°
_____________________
angle ADB + angle ADE = 180 ( linear pair)
=) 140 + angle ADE = 180
=) x = 40 °
_______________________
In triangle ADE,
=) angle ADE + angle AED + angle DAE = 180
=) 40 + angle AED + 50 = 180
=) angle AED + 90 = 180
=) angle AED = 90°
________________________
angle AED + angle AEC = 180 ( linear pair)
=) 90 + y = 180
=) y = 90°
_________________________
In triangle AEC,
angle AEC + angle ACE + angle EAC = 180
=) y + z + 60 = 180
=) 90 + z + 60 = 180
=) z = 180 - 150
=) z = 30 °
Hence, x = 40°
y = 90°
z = 30°
Then,
angle ABC = angle ACB = 30°
Since, if base angles are equal then , the triangle is isosceles triangle.
Hence, Triangle ABC is an isosceles triangle.
Hope it helps u.
In triangle ABD,
By angle sum property,
angle ABD + angle ADB + angle BAD = 180
=) 30 + angle ADB + 10 = 180
=) angle ADB = 180 - 40
=) angle ADB = 140°
_____________________
angle ADB + angle ADE = 180 ( linear pair)
=) 140 + angle ADE = 180
=) x = 40 °
_______________________
In triangle ADE,
=) angle ADE + angle AED + angle DAE = 180
=) 40 + angle AED + 50 = 180
=) angle AED + 90 = 180
=) angle AED = 90°
________________________
angle AED + angle AEC = 180 ( linear pair)
=) 90 + y = 180
=) y = 90°
_________________________
In triangle AEC,
angle AEC + angle ACE + angle EAC = 180
=) y + z + 60 = 180
=) 90 + z + 60 = 180
=) z = 180 - 150
=) z = 30 °
Hence, x = 40°
y = 90°
z = 30°
Then,
angle ABC = angle ACB = 30°
Since, if base angles are equal then , the triangle is isosceles triangle.
Hence, Triangle ABC is an isosceles triangle.
Hope it helps u.
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