Question

please Answer first and full explained answer I will mark u​

Answer 1

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OF S THEN MARK AS BRILLIANT

Answer 2

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To simplify:

• $\left(\dfrac{8}{27}\right)^{\frac{-2}{3}} - \left(\dfrac{1}{3}\right)^{-2} - 7^0$

Solution:

$\left(\dfrac{8}{27}\right)^{\frac{-2}{3}} - \left(\dfrac{1}{3}\right)^{-2} - 7^0 \\\\\implies \left(\dfrac{2^3}{3^3}\right)^{\frac{-2}{3}} - \left(\dfrac{1}{3}\right)^{-2} - 1 \\\\\implies \left(\dfrac{2}{3}\right)^{\frac{-2*3}{3}} - \left(\dfrac{1}{3}\right)^{-2} - 1 \\\\\implies \left(\dfrac{2}{3}\right)^{-2} - \left(\dfrac{1}{3}\right)^{-2} - 1 \\\\\implies \left(\dfrac{2}{3} -\dfrac{1}{3}\right)^{-2} - 1 \\\\\implies \left(\dfrac{1}{3}\right)^{-2} - 1 \\\\\implies 3^2 - 1 \\\\\implies 9 -1 \\\\\bold{\implies 8}$

Hope it helps!!