Question

please answer for above question its urgent

Answer 1

$cos(A - B) = \sqrt{3}/2 ; sin (A + B) = \sqrt{3}/2$

$A - B = 30^o | A + B = 60^o$

$A - B - (A+B) = 30 - 60$

$A - B - A - B = -30$

$-2B = -30$

∴$B = 15^o$

Substitute B = 15 in any one of the equations!

$A - B = 30$

$A - 15 = 30$

∴$A = 45^o$

Answer 2

cos(A-B)= root 3/2
therefore A-B = 30                    (1)
sin(A+B)= root 3/2
therefore A+B = 60                   (2)
from 1 and 2
A = 45
B = 15
Hope this helps
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