Math, asked by manoj4164, 11 months ago

Please answer for this.. ​

Attachments:

Answers

Answered by vishnurohit
1

Answer:

AB+AC=9

AC=9–AB

wkt

AC*2=AB*2+BC*2

(9–AB)*2=AB*2+BC*2

81+AB*2–18AB=AB*2+BC*2

wkt

BC=3

81–18AB=(3)*2

18AB=81–9

18AB=72

AB=4

AB+AC=9

4+AC=9

AC=5

then

Sec C=5/3

sin*2 C+cos*2 C=1

Answered by xainlone856
4

Answer:

hyy mate

Step-by-step explanation:

i think first answer is right.........

Similar questions