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Answer: -5
Step-by-step explanation:
Let the same common difference of two AP's = d
1st term of 1st AP, a= 2
1st term if 2nd AP , b= 7
A/q,
a10-b10= a25-b25
Using, tn= a+(n-1) d, we get
a+9d-(b+9d) = a+24d-(b+24d)
a +9d - b - 9d) = a+24d- b-24d
a- b= a-b, Hence, it is always same for any two AP's having same common difference (d) , whether 1st terms given Or not.
[Also, a-b = 2-7= -5, thus difference between any two corresponding terms of AP's is always -5]
Conclusion: the difference between any two corresponding terms of such AP’s is the same as the difference between their first terms
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