Question

please answer for this question ​

Answer 1

Answer:

3. AD is the median

4. angle ACD= 90⁰

Therefore, angleACB =90⁰

In ∆ABC,

90⁰+50⁰+x⁰=180⁰

x⁰=180⁰-140⁰=40⁰

x=40⁰

5. In ∆PQR, by angle sum property

x⁰+x⁰+x⁰= 180⁰

3x⁰=180⁰

x⁰=180⁰/3 =60⁰

x=60⁰

Answer 2

ans : 3) - In triangle abc ,

if "D" is the mid point then line segement "AD" is the "Median"of the triangle abc...

ans : 4) - In triangle abc ,

Given, angle "B" = 50°

and exterior angle "c" = 90°

then, interior angle"c" also = 90° ( linear pair. of angles)

Now,

angle "b" + angle "c" + angle "a" = 180° ( angle sum property of a triangle)

= 50° + 90° + "X" = 180°

= 140° + "X" = 180°

= "X" = 180° - 140°

= "x" = 40°

ans 5) - In triangle PQR,

the value of all the 3 angles are equal because there value is given as "x"

therefore,

x + x + x = 180° ( angle sum property)

= 3x = 180°

= x = 180°/3

= x = 60°

hence, the value of each side is 60°

well hope it helps...