Question

please answer for this question..​

Answer 1

comparing with the general form of the equation ax^+bx+c=0

a=(a-b)

b=(b-c)

c=(c-a)

b^-4ac=(a-b)^2-4*(b-a) (c-a)

=a^2-2ab+b^2-4b-4a(c-a)

=a^2-2ab+b^2-4bc-4a^2

but b^2-4ac=0

a^2-2ab+b^2-4bc-4a^2=0

a^2-4a^2+2ab+b^2-4bc=0