please answer for this question... fast
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Hey
Hope this helps you :)
Have a nice day
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shabhana:
i can't understand the second step
please explain it
okk
i understand
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[2sin^243°+1+cos^2 (90°-43°)]/[3cos^263°-2+3sin^2 (90-27°)]
(because of cosA=sin (90°-A)and sinA=cos (90°-A))
2[sin^243°+cos^243°+1]/3 (cos^263°+sin^263°)-2]
2+1/3-2 (sin^2A+cos^2A=1)
3/1
so the answer is 3
(because of cosA=sin (90°-A)and sinA=cos (90°-A))
2[sin^243°+cos^243°+1]/3 (cos^263°+sin^263°)-2]
2+1/3-2 (sin^2A+cos^2A=1)
3/1
so the answer is 3
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