please answer for this question fastly
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given,
p(x)=2x^4-5x^2-7x+5
q(x)=2x^3-3x+4
so, p(x)=2x^4+0x^3-5x^2-7x+5
q(x)=2x^3+0x^2-3x+4
now add both and subtract and again you substitute the value of x as 1.
hope this will help u
p(x)=2x^4-5x^2-7x+5
q(x)=2x^3-3x+4
so, p(x)=2x^4+0x^3-5x^2-7x+5
q(x)=2x^3+0x^2-3x+4
now add both and subtract and again you substitute the value of x as 1.
hope this will help u
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