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here is your answer
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(i) BDsquare = ADsquare +ABsquare
41square= ADsquare+ 40square
1681= ADsquare+ 1600
AD= √81
= 9cm
ii) area of trepazium =1/2 (sum of parellel sides )*hight
= 1/2(15+40)*9
1/2 *55*9
= 495/2cm squars
iii) areaof BCD= area of trepizum - area of ABD
41square= ADsquare+ 40square
1681= ADsquare+ 1600
AD= √81
= 9cm
ii) area of trepazium =1/2 (sum of parellel sides )*hight
= 1/2(15+40)*9
1/2 *55*9
= 495/2cm squars
iii) areaof BCD= area of trepizum - area of ABD
discount:
9 cm
correct
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