Question

please answer friends ​

Answer 1

Solution :-

given that,

→ A = {2, 3, 5, 7}

→ B = {1, 2, 4, 5}

we know that,

• A - B = The set of elements that are in A but not in B . Or we can say that, the set of elements belongs to A only .

so,

→ A - B = {2, 3, 5, 7} - {1, 2, 4, 5}

as we can see that, {2 , 5} are common ,

then,

→ A - B = {3, 7} (Ans.)

Method (2) :-

→ A - B = A - (A ∩ B)

so,

→ A = {2, 3, 5, 7}

→ B = {1, 2, 4, 5}

then,

→ A ∩ B = {2, 5}

therefore,

→ A - B = {2, 3, 5, 7} - {2, 5}

→ A - B = {3, 7} (Ans.)

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Answer 2

SOLUTION

TO FILL IN THE BLANKS

6. If A = { 2 , 3 , 5 , 7 } and B = { 1 , 2 , 4 , 5 } then A - B = _______

7. If U = { 2 , 4 , 6 , 8 , 10 } and P = { x : x is an even prime number } then P' = ________

8. If A = { x : x is a letter in the word " INDIA " } and B = { x : x is a letter in the word " HINDI " } then A ∩ B = ______

9. A set which has one element is called _____ set

10. The set and its complement is always ______

EVALUATION

ANSWER TO QUESTION : 6

A = { 2 , 3 , 5 , 7 }

B = { 1 , 2 , 4 , 5 }

A - B

= { x ∈ A : x ∉ B }

= { 3 , 7 }

ANSWER TO QUESTION : 7

U = { 2 , 4 , 6 , 8 , 10 }

P = { x : x is an even prime number }

Since 2 is the only even prime number

∴ P = { 2 }

∴ P'

= { x ∈ U : x ∉ P }

= { 4 , 6 , 8 , 10 }

ANSWER TO QUESTION : 8

A = { x : x is a letter in the word " INDIA " }

∴ A = { I , N , D , A }

B = { x : x is a letter in the word " HINDI " }

∴ B = { H , I , N , D }

A ∩ B

= { x : x ∈ A & x ∈ B }

= { I , N , D }

ANSWER TO QUESTION : 9

We know that set is a well defined collection of distinct objects of our perception

Now if a set contains one element , then the set is called singleton set

Thus we can conclude that :

A set which has one element is called singleton set

ANSWER TO QUESTION : 10

We know that for a given set P we have

P'

= The complement set of P

= { x ∈ U : x ∉ P }

So P and P' has no common element

∴ P ∩ P' = Φ

So P and P' are disjoint set

Thus we can conclude that :

The set and its complement is always disjoint

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