Math, asked by ITSMETHEKING, 10 months ago

please answer from question 4 to 13 fast

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Answered by mallinettem
0

Answer:

4 ) 1) 1 - cos²theta 1 + ( cos theta /sin theta )² )

sin²theta × sin² theta +cos² theta /sin²theta

sin²theta /sin² theta ×1

=1

4) 2) 1/ sin theta 1+cos theta cosec theta -cot theta

1 +cos theta / sin theta 1 /sin theta -cos theta /sin theta

1 + cos theta /sin theta 1- cos theta /sin theta =1²-cos²theta /sin ²theta

sin ²theta /sin ²theta =1

Answered by suruthi21
1

See it took time for me to answer so please mark me as brainliest

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