please answer give me tomorrow exam
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tan(20-3α)=cot(5α-20)
⇒tan(20-3α)=tan(90-(5α-20))
⇒20-3α=90-5α+20
⇒5α-3α=110-20
⇒2α=90
⇒α=90/2
⇒α=45
⇒tan(20-3α)=tan(90-(5α-20))
⇒20-3α=90-5α+20
⇒5α-3α=110-20
⇒2α=90
⇒α=90/2
⇒α=45
himanshu32:
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