Physics, asked by anushka112006, 1 month ago

Please answer guys it's urgent​

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Answered by sivakumar20dec
0

1) OB

2)CD

3) 4√2m

hope you find this helpful.

Answered by inamdaraaman26
0

Answer:

1) BC

2)AB and CD

3) For calculating distance,

= In triangle ABE +In Rectangle BCFE +In triangle FCD

= (1/2×AE×BE) +(BC×CF) + (1/2×FD×CF)

=(1/2×4×4)+(6×4)+(1/2×4×4)

=8+24+8

=40 sq cm

I hope u get it

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