Question

Please answer guys please​

Answer 1

Answer:

ScholrScholrLogin

ques_image

- 5. In Fig 7.51, PR > PQ and PS bisects 2 QPR. Prove that ZPSR > 2 PSQ. *Thes Fig. 7,51

Mathematics

WhatsApp_icon

fb_icon

2 Answers

user_img

Krishnadeva Andra

Grade 10

follow

Given:

PR > PQ & PS bisects ∠QPR

To prove:

∠PSR > ∠PSQ

Proof:

∠PQR > ∠PRQ — (i) (PR > PQ as angle opposite to larger side is larger.)

∠QPS = ∠RPS — (ii) (PS bisects ∠QPR)

∠PSR = ∠PQR +∠QPS — (iii)

(exterior angle of a triangle equals to the sum of opposite interior angles)

∠PSQ = ∠PRQ + ∠RPS — (iv)

(exterior angle of a triangle equals to the sum of opposite interior angles)

Adding (i) and (ii)

∠PQR + ∠QPS > ∠PRQ + ∠RPS

⇒ ∠PSR > ∠PSQ [from (i), (ii), (iii) and (iv)]

STAY BLESSED ✨