Question

Please answer his question immediately

Answer 1

Given :- ST || RQ, PS=3cm and SR=4cm.
We know that the ratio of areas of two similar ∆s is equal to the ratio of squares of their corresponding sides.
ar(∆PST)/ar(∆PRQ) = (PS)²/(PR)²
= (3)²/(PS+SR)²
= (3)²/(3+4)²
= (3)²/(7)²
= 9/49
Hence, the required ratio of ∆PST : ∆PRQ = 9:49