Question

please answer i and ii ​

Answer 1

Answer:

,

Step-by-step explanation:

please refer to the attached picture

Answer 2

Step-by-step explanation:

#BAL

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Factorise the following..

(1) a²+10a+24

(2) x² +9x +18

$\huge\red{\underline{\underline{\bf Answer:-}}}$

$(1) \\ \leadsto {a}^{2} + 10a + 24 = 0 \\ \\ Comparing \: \: with \: \: a {x}^{2} + bx + c = 0 \\ \\ a = 1 \\ b = 10 \\ c = 24 \\ \\ using \: \: formula \: \: method \: \: \implies \\ \\ a = \frac{ - b + \: or \: - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ \implies a = \frac{ - 10 + \: or \: - \sqrt{100 - 4(24)} }{2(1)} \\ \\ \implies a = \frac{ - 10 + \: or \: - \sqrt{100 - 96} }{2} \\ \\ \implies a = \frac{ - 10 + \: or \: - \sqrt{4} }{2} \\ \\ \implies a = \frac{ - 10 + 2}{2} \: \: \: \: or \: \: \: \: a = \frac{ - 10 - 2}{2} \\ \\ \implies a = \frac{ - 8}{2} \: \: \: \: or \: \: \: \: a = \frac{ - 12}{2} \\ \\ \huge \boxed{ \implies a = - 4 \: \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: a = - 6 }$

$(2) \\ \leadsto {x}^{2} + 9x + 18 = 0 \\ \\ Comparing \: \: with \: \: a {x}^{2} + bx + c = 0 \\ \\ a = 1 \\ b = 9 \\ c = 18 \\ \\ using \: \: formula \: \: method \: \: \implies \\ \\ x = \frac{ - b + \: or \: - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ \implies x = \frac{ - 9 + \: or \: - \sqrt{81 - 4(18)} }{2(1)} \\ \\ \implies x = \frac{ - 9 + \: or \: - \sqrt{81 - 27} }{2} \\ \\ \implies x = \frac{ - 9 + \: or \: - \sqrt{9} }{2} \\ \\ \implies x = \frac{ - 9 + 3}{2} \: \: \: \: or \: \: \: \: x = \frac{ - 9 - 3}{2} \\ \\ \huge \boxed{ \implies x = - 3 \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \: x = - 6}$

# BAL