Question

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Answer 1

Answer:

$\frac{ {(4)}^{n + 1}. {2}^{n} - {8}^{n} }{ {2}^{2n} } = \frac{3}{8} \\ \\ \frac{4.( {2}^{n} )( {2}^{n})( {2}^{n} ) - {(2)}^{n} {2}^{n} . {2}^{n} }{ {2}^{n}. {2}^{n} } = \frac{3}{8} \\ \\ {2}^{n} (3) = \frac{3}{8} \\ \\ {2}^{n} = {2}^{- 3} \\ \\ n = - 3$

Answer 2

Answer:

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