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BD = BC-DC
BD = 21-5
BD = 16
in triangle ADC
h² = b² + p²
13² = 5² + AD²
169 = 25 + AD²
169-25 = AD²
AD² = 144
AD² = 12²
AD = 12
in triangle ADB
h² = b² + p²
AB² = 16² + 12²
AB² = 256 + 144
AB² = 400
AB² = 20²
AB = 20
sec thitta = AB/BD
= 20÷16
= 5/4
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