Question

please answer I will give 20 thanks to your answers if u answer correctly​

Answer 1

Step-by-step explanation:

GIVEN EQUATION

$2 {x}^{3} - 3 {x}^{2} + ax + b$

GIVEN 0 AND 1 ARE ZEROES

PUTTING x=1

$2(1) {}^{3} - 3(1) {}^{2} + a(1) + b = 0$

$2 - 3 + a + b = 0$

$a + b = 1$

PUTTING X=0

$2(0) {}^{3} - 3(0) {}^{2} + a(0) + b = 0$

$b = 0$

$a + b = 1$

$a + 0 = 1$

$a = 1$

HENCE a=1 and b=0

Answer 2

Answer:

here's ur answer mate....

Step-by-step explanation:

please give me 20 thanx