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![\begin{cases}d(1)=\dfrac{1}{12}\\\\ d(n)=d(n-1)\cdot (-6) \end \begin{cases}d(1)=\dfrac{1}{12}\\\\ d(n)=d(n-1)\cdot (-6) \end](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dd%281%29%3D%5Cdfrac%7B1%7D%7B12%7D%5C%5C%5C%5C+d%28n%29%3Dd%28n-1%29%5Ccdot+%28-6%29+%5Cend)
What is the 4th term in the sequence?
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hi hello I don't know the answer
Actually thanks for the 5 points
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