please answer i will mark u brainlest for sure (only q7.8.9)
Answers
7.
In ∆ DEM & ∆DFM
angle EDM = angle MDF ( given)
DM = DM ( common)
angle DME = DMF (90°)
=> ∆ DEM is congruent to ∆ DFM (ASA congruency criteria)
Therefore, DE = DF (CPCT)
Since, two sides of ∆ DEF is equal, it is an isosceles triangle.
8.
angle B = angle E
48 ° = 2z + 18°
30° = 2z
15° = z
Angle F = Angle C
42° = x/2
42° × 2 = x
84° = x
In ∆ ABC,
angle A + angle B + angle C = 180°
(y + 40°) + 48° + 42° = 180°
130° + y = 180°
y = 180° - 130°
y = 50°
Hope it helps.
(Please, instead of making me brainliest, drop some thanks for some of my questions.)
Answer:
7.
In ∆ DEM and ∆ DFM
angle EDM = angle MDF (given)
DM = DM ( common )
angle DME = DMF (90°)
= ∆ DEM is congruent to ∆ DFM ( ASA congruency criteria)
THEREFORE ,DE = DF (CPCT)
since , two sides of ∆ DEF is equal, it is sn isosceles triangle.
8.
angle B = angle E
48° = 2z + 18°
30° = 2z
15° = z
angle F = angle C
42° = x/2
42° × 2 = x
84° = x
in ∆ ABC ,
angle A + angle B + angle C = 180°
(y + 40°) + 48° + 42° = 180°
130° + y = 180°
y= 180° - 130°
y = 50°
Step-by-step explanation:
hope it helps you..