Please answer if answered correctly I will give 100 points afterwards
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Showed SinA.CosA=√2/4
Step-by-step explanation:
TanA=√2-1 (given)
TanA=P/B=√2-1/1
According to Pythagoras
H²=P²+B²
H²=(√2-1)²+1²
H²=2+1-2√2+1
H=√(4-2√2)
SinA.CosA=P/H*B/H
SinA.CosA=(√2-1).1/√(4-2√2)
SinA.CosA=(√2-1)/2√2(√2-1) {take 2√2 common from √(4-2√2)}
SinA.CosA=1/2√2
(Multiply and Divide √2 in numerator and denominator)
SinA.CosA=√2/4
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