Question

please answer if it is very hard for me to solve

Answer 1

Solve it step by step:-

First:

$\frac{2m}{3} - \frac{5m^2}{3} +\frac{5m^3}{2}$

Taking 6 as the LCM:

$\implies \frac{4m-10m^2+15m^3}{6}$ ..............................(1)

Next :

$\implies -\frac{4}{3}+\frac{2m^2}{3}-\frac{m}{2}$

$\implies \frac{-8+4m^2-3m}{6}$.............................(2)

Adding 1 and 2 gives:

$\implies \frac{4m-10m^2+15m^3-8+4m^2-3m}{6}$

$\implies \frac{m-6m^2+15m^3-8}{6}$.....................(3)

Now is this going to end:

$\implies \frac{5m^3}{3}+3m^2+3m+\frac{6}{5}$

$\implies \frac{25m^3+45m^2+45m+18}{15}$.....................(4)

Ok

Adding (3) and (4) gives :

$\implies \frac{5m-30m^2+75m^3-40+50m^3+90m^2+90m+36}{30}$

$\implies \frac{95m+60m^2+125m^3-4}{30}$

Add the first two to this:

$\implies \frac{95m+60m^2+125m^3-4}{30}+2$

$\implies \frac{95m+60m^2+125m^3-4+60}{30}$

$\implies \frac{95m+60m^2+125m^3+56}{30}$

$\implies \frac{95m}{30}+\frac{60m^2}{30}+\frac{125m^3}{30}+\frac{56}{30}$

$\implies \frac{19m}{5}+2m^2+\frac{25m^3}{6}+\frac{28}{15}$

Your answer: Option C

Hope it helps you