Math, asked by BrainofBrainly, 1 year ago

Please answer. If tanA= m/n find the value of msinA + ncosA / msinA - ncosA

Answers

Answered by mysticd

Hi ,

tanA = m / n -----( 1 )

( msinA + n cosA ) / ( msinA - n cosA)

divide numerator and denominator

with cos A

= (msinA/cosA+ncosA/cosA)/(msinA/cosA-ncosA/cosA)

= (mtanA +n)/(mtanA-n)

= [(m×m/n )+n] /[(m×m/n )-n]

from ( 1 ),

=[(m² +n² ) /n]/ [(m² - n²)/n]

'n ' is cancelled

= ( m² + n² )/(m² - n² )

I hope this helps you.

:)

BrainofBrainly: Thanx

BrainofBrainly: But I didn't understand after (mtanA+n) ........

mysticd: tanA = m / n ( given) put it in the expression

mysticd: (m × m / n )+ n = ( m² + n² ) n doing lcm

mysticd: Thank you Ashowrya

BrainofBrainly: thank you!!

Answered by sandy1816

Answer:

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