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if the valency of an element e is 3. then deduce the chemical formula for nitrate sulfide and phosphate​

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MSO

4

is the formula of sulphate of metal M. Write down the formula of its :

i) Hydroxide ii) Chlorite iii) Chloride

iv) Nitrate v) Nitrite vi) Peroxide

vii) Chromate viii) Phosphate.

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Solution

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For given formula of sulphate of metal, its valency is +2.

(i) OH

−

is hydroxide ion. By balancing charge, formula of metal hydroxide ion is M(OH)

2

.

(ii) ClO

2

−

is chlorite ion. We need 2 such ions for charge balance. Hence metal chlorite M(ClO

2

)2.

(iii) Chloride has Cl

−

ion. Hence, metal chloride is MCl

2

.

(iv) NO

3

−

is nitrate ion. By charge balance, metal nitrate is M(NO

3

)

2

.

(v) NO

2

−

is nitrite ion. Hence M(NO

2

)

2

is metal nitrite.

(vi) Peroxide has O

−

ion. By charge balance, metal peroxide is MO

2

.

(vii) CrO

4

2−

is chromate ion. Hence, by balancing charges metal chromate is M(CrO

4

).

(viii) (PO

4

)

3−

is phosphate ion. By charge balance, metal phosphate is M

3

(PO

4

)

2

.