Math, asked by snahadebbarma, 6 months ago

please answer if you know ​

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Answered by Snapskg730
2

Answer:

  \frac{ \sqrt{3 }  + 2}{ \sqrt{3  -  2 } }  \times  \frac{ \sqrt{3 } + 2 }{ \sqrt{3 + 2} }

 \frac{( \sqrt{3 } + 2) {}^{2}  }{ (\sqrt{3} ) {}^{2} - ( 2) {}^{2} }

 \frac{( \sqrt{3}) {}^{2}  + (2) {}^{2} + 2( \sqrt{3})(2)   }{3 - 4}

 \frac{3 + 4 + 4 \sqrt{3} }{ - 1}

 - 7 + 4 \sqrt{3}

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