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angle AQB=angle BPA =90°
AB=AB is common in both triangles
angle QAB= angle BAP(AB is the bisector of angle A)
so by ASA
∆ AQB congruence to ∆ APB
so by cpct BQ = BP
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Here is Your Answer !!
Given :-
angle AQB = angle APB = 90°
Since line L is angle bisector so angle QAB = angle PAB
In ∆ APB and ∆ AQB
angle QAB = angle PAB { line L is angle bisector}
AB = AB { common }
angle AQB = angle APB = 90°
Hence, ∆ APB and ∆ AQB is congruent by ASA Congruency.
Since , ∆ APB and ∆ AQB is congruentso BY C.P.C.T BQ = BP
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