Math, asked by neha96248, 1 year ago

please answer immediately​

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Answered by saurabh6295
3

Answer:

angle AQB=angle BPA =90°

AB=AB is common in both triangles

angle QAB= angle BAP(AB is the bisector of angle A)

so by ASA

∆ AQB congruence to ∆ APB

so by cpct BQ = BP

Answered by Anonymous
141

Here is Your Answer !!

Given :-

angle AQB = angle APB = 90°

Since line L is angle bisector so angle QAB = angle PAB

In ∆ APB and ∆ AQB

angle QAB = angle PAB { line L is angle bisector}

AB = AB { common }

angle AQB = angle APB = 90°

Hence, ∆ APB and ∆ AQB is congruent by ASA Congruency.

Since , ∆ APB and ∆ AQB is congruentso BY C.P.C.T BQ = BP

#ALLENITE (◍•ᴗ•◍)❤

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