Math, asked by Byuti, 2 months ago

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Answered by Anonymous
15

Given to solve :-

 \dfrac{(5 \times 10 {}^{ - 36}) (3 \times 10 {}^{8} )}{10 \times 10 {}^{ - 24} }

SOLUTION:-

In the numerator open the brackets

 \dfrac{5 \times 10 {}^{ - 36 } \times 3 \times 10 {}^{8}  }{10 \times 10 {}^{ - 24} }

Multiply the terms in Numerator

 \dfrac{15 \times 10 {}^{ - 36} \times 10 {}^{8}  }{10 \times 10 {}^{ - 24} }

As we know from exponent and laws

a {}^{m}  \times a {}^{n}  = a {}^{m + n}

By applying this formula to numerator and denominator we get

 \dfrac{15 \times 10 {}^{ - 36 + 8} }{10 { }^{ + 1 - 24} }

 \dfrac{15 \times 10 {}^{ - 28} }{10 {}^{ - 23} }

As we know ,

 \dfrac{a {}^{m} }{a {}^{n} }  = a {}^{m - n}

 \dfrac{15 \times 10 {}^{ - 28 - ( - 23)} }{1}

15  \times 10{}^{ - 28 + 23}

15 \times 10 {}^{ - 5}

 = 1.5 \times 10{}^{-6}

So,

 \dfrac{(5 \times 10 {}^{ - 36}) (3 \times 10 {}^{8} )}{10 \times 10 {}^{ - 24} }  = 1.5 \times 10 {}^{ - 6}


rsagnik437: Great :)
Answered by anurag21286
0

Answer:

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