Please answer.
In a group of dogs and their owners, there are exactly 20 heads and 64 legs. How many dogs are in the group?
Answers
Answer: 12 dogs
Step-by-step explanation:
Method 1: Strategy : Start with an extreme case.
Note* 20 heads means 20 creatures.
Suppose all creatures are owners(human beings). There would then be a total of 40 legs because a human being has 2 legs, 20 creatures×2 legs=40 legs.
The extra 24 legs ( 64 legs(total legs)-40 legs) must be accounted for by the dogs. Since each dog has 2 more legs than its owner, there are 24÷2=12 dogs
Method 2: Strategy: Set up a table and look for a pattern.
The number of legs is 2 times the number of owners plus 4 times the number of dogs.
- Number of owner 20 19 18 17 ....... ?
- Number of dogs 0 1 2 3 ....... ?
- Number of legs 40 42 44 46 ...... ?
Each increase of 1 in the number of dogs increases the number of legs by 2. To increase from 40 legs to 64 legs, a total of 24, requires an increase of 12 in the number of dogs. There are 12 dogs in the group.
Method 3: Strategy: Use algebra.
Let D = the number of dogs. Then 20-D= the number of owners and
4D+2(20-D)=the number of legs.
4D+2(20-D)=64
Solving:
4D+40-2D=64
2D+40=64
2D=64-40
2D=24
∴D=24
There are exactly 12 dogs in the group.
Answer: 12 dogs
We know that a dog has 4 legs and a man has 2 legs.
As there are 20 heads, there are 20 members.
First we have to divide the total no. of legs by the total no. of heads, to get the average no. of legs.
Thus the average is 3.2.
Now the ratio of no. of dogs to that of the owners is,
Average - No. of legs of one owner : No. of legs of one dog - Average
Thus the ratio is 3 : 2. Taking 12 : 8 for better.
In 12 : 8 ratio, we get that the total no. of members is 20, which is equal to the no. of heads. Thus the no. of dogs and that of owners would be equal to this ratio numerically, and thus the no. of dogs is 12.
Also, on taking 3 : 2,
No. of dogs =