Question

Please answer in brief

Answer 1

$2 {x}^{2} - 2 \sqrt{2} x + 1 = 0 \\ \\ 2 {x}^{2} - \sqrt{2} x- \sqrt{2} x + 1 = 0 \\ \\ \sqrt{2} x( \sqrt{2} x - 1) - 1( \sqrt{2} x - 1) = 0 \\ \\ ( \sqrt{2} x - 1)( \sqrt{2} x - 1) = 0 \\ \\ \\ \\ x = \frac{1}{ \sqrt{2} }$

Answer 2

2x²-2√2x+1=0



so by quarditic formula
α and β= -b+-√b²-4ac/2a
            =2√2+-√8-8/2a
            =2√2+-0/2a
α=2√2/2
 =1/√2
and
β=2√2/2
 =1/√2