Question

please answer in class 7 method I will mark you as brainliest​

Answer 1

Given, that a = 2 and b = -2

First, let us find $a^{2}$

Putting value of a, we get

$a^{2}=2^2\\=4$

Secondly, for $ab$

Putting values of a and b, we get

$ab=a\times b\\=2\times(-2)\\= 2 \times (2\times-1)\\=-1\times(2\times2)\\=-1\times4\\=-4$

And, for $b^{2}$

$b^2 =(-2)^2\\=(-1\times 2)^2=\\(-1)^2\times 2^2\\=1\times 4\\=4$

Now, substituting values of $a^{2},ab,b^{2}$, we get

$a^2+ab+b^2\\= 4 + (-4) + 4\\= 4-4+4\\=0+4\\=4$

Answer 2

Step-by-step explanation:

please answer in class 7 method I will mark you as brainliest