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( √x - 1/√x )^2
use (a-b)^2 formula.
i.e.,
=> (√x)^2 - 2.√x.1/√x + (√x)^2 = 0
=> x - 2 + 1/x = 0
=> x^2 - 2x + 1 = 0
=> x^2 -(1+1) x +1 = 0
=> x^2 - x-x + 1 = 0
=> x(x-1) - 1(x-1) = 0
=> (x-1)(x-1) =0
=> x= 1,1
use (a-b)^2 formula.
i.e.,
=> (√x)^2 - 2.√x.1/√x + (√x)^2 = 0
=> x - 2 + 1/x = 0
=> x^2 - 2x + 1 = 0
=> x^2 -(1+1) x +1 = 0
=> x^2 - x-x + 1 = 0
=> x(x-1) - 1(x-1) = 0
=> (x-1)(x-1) =0
=> x= 1,1
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