Math, asked by neha553, 1 year ago

please answer in full method no.v

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Answered by MarkAsBrainliest
1
Answer :

(v)

Now, (x + 2y)(- 3x - y) - (x + y)(x - y) + (x - 2y)(- 2x + y)

= (- 3x² - xy- 6xy - 2y²) - (x² - xy + xy - y²) + (- 2x² + xy + 4xy - 2y²)

= (- 3x² - 7xy - 2y²) - (x² - y²) + (- 2x² + 5xy - 2y²)

= - 3x² - 7xy - 2y² - x² + y² - 2x² + 5xy - 2y²

= (- 3 - 1 - 2)x² + (- 7 + 5)xy + (- 2 + 1 - 2)y²

= - 6x² - 2xy - 3y²

= - (6x² + 2xy + 3y²)

#MarkAsBrainliest
Answered by Pranav777
1
Carefully go through the sum you will get the answer Mark me brain least please
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