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if a+b+c=0
a^3+b^3+c^3=3abc
proof a+b+c=0
a+b=-c
cubing both sides,,
(a+b)^3=,(-c)^3
a^3+b^3+3ab(a+b) = -c^3
putting the value of a+b
a^3+b^3abc=-c^3
a^3+b^3+c^3=3abc
a^3+b^3+c^3=3abc
proof a+b+c=0
a+b=-c
cubing both sides,,
(a+b)^3=,(-c)^3
a^3+b^3+3ab(a+b) = -c^3
putting the value of a+b
a^3+b^3abc=-c^3
a^3+b^3+c^3=3abc
SpoorthiMenda:
I don't think so..They are determinants na!
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