Question

please answer , irrelevant answers will be reported

Answer 1

Step-by-step explanation:

Given :-

Rate of interest = 6 2/3%

To find :-

In what time will a sum of money put at 6 2/3% simple interest becomes 4 times of itself ?

Solution :-

Let the principle be Rs. X

Rate of interest = 6 2/3%

=> R = [(6×3)+2]/3 %

=> R = (18+2)/3 %

=> R = 20/3%

Amount = 4 times the sum = Rs. 4X

Let the required time be T years

Simple Interest = Amount - Principle

=> SI = 4X - X

=> SI = Rs. 3X

We know that

Simple Interest = PTR/100

On substituting these values in the above formula then

=> 3X = (X×T×20)/(3×100)

=> 3X = 20XT/300

=> 3 = 20T/300

=> 3×300 = 20T

=> 900 = 20T

=> 20T = 900

=>T = 900/20

=> T = 45 years

The required time = 45 years

Answer:-

The sum becomes 4 times of itself in 45 years

Check:-

Principle = Rs. X

Time = 46 years

Rate of interest = 6 2/3 = 20/3 years

SI = PTR/100

=> SI = (X×45×20)/(3×100)

=> SI = 900X/300

=> SI = 3X

Amount = P+I

=>A = X+3X

=> A = 4X

=> Amount = 4 times the principle.

Verified the given relations in the given problem.

Used formulae:-

• Simple Interest = PTR/100
• Amount = P+I
• P = Principle
• T = Time
• R = Rate of Interest