Question

please answer it.....

Answer 1

hi friend
here's your answer looking for

here, the sound get reflected at the bottom. so, the distance get doubled.

Hence, the distance travelled by a sound = 2s

time (t) = 2.5sec

velocity of sound (v) = 330m/s

so, we know that,

$v = \frac{s}{t}$

so, here distance get doubled that's why

$v = \frac{2s}{t} \\ \\ 330 = \frac{2s}{2.5} \\ \\ 330 \times 2.5 = 2s \\ \\ 825 = 2s \\ \\ s = \frac{825}{2} \\ \\ s = 412.5$
so, distance= s= 412.5 m

hope you are satisfied with my answer

Answer 2

Answer:

hi friend

here's your answer looking for

here, the sound get reflected at the bottom. so, the distance get doubled.

Hence, the distance travelled by a sound = 2s

time (t) = 2.5sec

velocity of sound (v) = 330m/s

so, we know that,

v = \frac{s}{t}v=

t

s

so, here distance get doubled that's why

\begin{gathered}v = \frac{2s}{t} \\ \\ 330 = \frac{2s}{2.5} \\ \\ 330 \times 2.5 = 2s \\ \\ 825 = 2s \\ \\ s = \frac{825}{2} \\ \\ s = 412.5\end{gathered}

v=

t

2s

330=

2.5

2s

330×2.5=2s

825=2s

s=

2

825

s=412.5

so, distance= s= 412.5 m

hope you are satisfied with my answer