Question

please answer it...​

Answer 1

Answer:

$\sf \huge \underline \green{Given:} \\ \\ \sf{ \implies \: Volume_{(cone)} = 1212 {cm}^{3}} \\ \\ \\ \sf \huge\underline \red{To Find;} \\ \\ \ \sf{ \implies \: Surface \: Area:_{(cone)}} \\ \\ \sf \huge \underline \blue{Solution:} \\ \\ \sf \: \frac{1}{3}\pi {r}^{2}h = 1212 \\ \\ \sf \: \frac{1}{3} \times \frac{22}{7} \times {r}^{2} \times 24 = 1212 \\ \\ \sf \: {r}^{2} = 49(approx.) \\ \\ \sf \: r = 7(approximately) \\ \\ \: \\ \\ \sf \: {l}^{2} = {h}^{2} + {r}^{2} \\ \\ \sf \: {l}^{2} = {24}^{2} + {7}^{2} \\ \\ \sf \: {l}^{2} = 625 \\ \\ \sf l= 25 \: cm \\ \\ \sf Surface \: Area =\pi {r}^{2} + \pi \: rl \\ \\ \sf \frac{22}{7} \times {7}^{2} + \frac{22}{7} \times 7 \times 25 \\ \\ \sf \: 154 + 550 \\ \\ \sf \: 704 \: {cm}^{2}(approximately)$